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In one of the satellites of Jupiter has an orbital period of 1.769 days and the radius of the orbit is 4.22 xx 10^8 m. Show that the mass of Jupiter is about one-thousandth that of the sun. |
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Answer» Solution :`implies`Orbital PERIOD of Jupiter T = 1.769 days = `= 1.769 XX 24 xx 3600 s` `= 1.528 xx 10^5 s` Radius of satellite, ` r = 4.22 xx 10^(8) m` ` G = 6.67 xx 10^(-11)Nm^(2)//KG^(2)` Mass of sun `= 2 xx 10^(30)`kg Suppose mass of Jupiter = `M_J` Centripetal = GRAVITATIONAL FORCE `:. (mv^2)/r = (GM_J.m)/r^2` `:. v^2 =(GM_J)/r` but `v = r omega` `:. r^(2)omega^2=(GM_J)/r` `:. omega^2=(GM_J)/r^3 ""[ :. omega=(2pi)/T]` `:. (4pi^2)/T^2=(GM_J)/r^3` `:. M_(J) = (4pi^2r^3)/(T^2G)` `:. M_J = (4 xx (3.14 )^2 xx(4.22xx10^8)^3)/((1.528xx10^5)^2xx6.67 xx10^(-11))` `~~ 1.903 xx 10^(27)kg ` `~~ 2 xx 10^(27) kg ` `:. M_J = M_s/1000` |
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