1.

In one organic compound the proportion of C, H & Cl is 10%, 0.84% and 89.2 % respectively.Its empirical formula is.....

Answer»

`C Cl_(4)`
`CHCl_(3)`
`CH_(3)CL`
`CH_(2)Cl_(2)`

Solution :`C:H:Cl=(10)/(12):(0.84)/(1) : (89.2)/(35.5)`
`=0.83:0.84:2.51`
`= (0.83)/(0.83) : (0.84)/(0.83) : (2.51)/(0.83)`
`= 1:1:3`
`:.CHCl_(3)`


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