1.

In optical communication system operating at 1200nm, only 2% of the source frequency is available for TV t ransmission having a bandwidth of 5 MHz. the number of TV channels that can be transmitted isA. 2 millionB. 10 millionC. 0.1 millionD. 1 million

Answer» Correct Answer - D
Optical source frequency, `v=(c)/(lambda)`
or `v=(3xx10^(8)xxms^(-1))/(1200xx10^(-9)m)=2.5xx10^(14)Hz`
Bandwidth of channel=2% of the source frequency
`=(2)/(100)xx2.5xx10^(14)Hz=5xx10^(12)Hz`.
Number of channels `=("Total bandwidth of channel")/("Bandwidth needed per channel")`
`=(5xx10^(12)Hz)/(5xx10^(6)Hz)=10^(6)`=1 million


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