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In order to establish an instantaneous displacemet current of 1 mA in the space between the plates of 2`mu`F parallel plate capacitor, the potential difference need to apply isA. `100 V s^(-1)`B. `200V s^(-1)`C. `300Vs^(-1)`D. `500 V s^(-1)` |
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Answer» Correct Answer - D `I_(D)="1 mA" =10^(-3)A,C=2muF=2xx10^(-6)F` `I_(D)=I_(C)=(d)/(dt)(CV)=C(dV)/(dt)` Therefore, `(dV)/(dt)=(I_(D))/(C)=(10^(-3))/(2xx10^(-6))=500"V s"^(-1)` Therefore, applying a varying potential difference of 500 V `s^(-1)` would produce a displacement current of desired value. |
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