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In order to obtain an output `Y=1` form the circuit of fig. the inputs must be A. `A=0,B=1,C=0`B. `A=1,B=0,C=0`C. `A=1,B=0,C=1`D. `A=1,B=1,C=0` |
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Answer» Correct Answer - C The boolean expression for the given combination is output `Y=(A+B)` truth table is `|(A,B,C,Y=(A+B).C),(0,0,0,0),(1,0,0,0),(0,1,0,0),(0,0,1,0),(1,1,0,0),(0,1,1,1),(1,0,1,1),(1,1,1,1)|` Hence `A=1,B=0,C=1` |
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