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In order to oxidise a mixture of one mole of each of FeC_2O_4,Fe_2(C_2O_4)_3,FeSO_4 and Fe_2(SO_4)_3in acidic medium , the number of mole of KMnO_4 required is |
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Answer» `2` `10Fe^(2+)+2MnO_4^(-) +16H^(+)rarr10Fe^(2+)+2MN^(2+)+8H_2O` `5C_2O_4^(2-)+2MnO_4^(-)+16H^(+)rarr2Mn^(2+)+10CO_2+8H_2O` For 1 mol of `C_2O_4^(2-)` mol of `KMnO_4` is NEEDED For mol of `C_2C_2O_4` , 2/5 mol of `KMnO_4` is needed `:.` For 1 mol of `FeC_2O_4` , moles of `KMnO_4` needed `=2/10+2/5=6/10` `Fe_2(C_2O_4)_3hArr2Fe^(3+)+3C_2O_4^(2-)` For 3 mol of `C_2O_4^(2-)` , moles of `KMnO_4` needed `=3xx2/5=6/5` `Fe^(3+)` is not affected by `KMnO_4` `FeSO_4 hArrFe^(2+)+SO_4^(2-)` 1 mol of `Fe^(2+)` require `KMnO_4=2/10` mol `Fe_2(SO_4)_3` is not affected by `KMnO_4` . TOTAL moles of `KMnO_4` required `=6/10+6/5+2/10=(6+12+2)/10=2` moles |
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