In Ostwald.s process for the manufacture of nitric acid, the first step involves the oxidation of ammonia gas by oxygen gas to give nitric oxide gas and steam. What is the maximum weight of nitric oxide that can be obtained starting only with 10.00 g. of ammonia and 20.00 g of oxygen ?

In Ostwald.s process for the manufacture of nitric acid, the first ste

1.	In Ostwald.s process for the manufacture of nitric acid, the first step involves the oxidation of ammonia gas by oxygen gas to give nitric oxide gas and steam. What is the maximum weight of nitric oxide that can be obtained starting only with 10.00 g. of ammonia and 20.00 g of oxygen ?
Answer» Solution :Balanced chemical reaction : `UNDERSET(=68gm)(underset(4xx17gm)(4NH_(3(g))))+underset(=160gm)(underset(5xx32gm)(5O_(2(g))))tounderset(=120gm)(underset(4xx30gm)(4NO_((g))))+underset(=108gm)(underset(6xx18gm)(6H_(2)O_((g))))` 68 gm of `NH_(3)` is USED with 160 gm `O_(2)`. `therefore10gmNH_(3)=(10xx190)/68=23.53gm` Here only 20 gm of `O_(2)` is given. Now, 160 gm `O_(2)` GIVES 120 gm NO. `therefore20gmO_(2)=(120xx20)/160=15gm` Therefore, 15 gm of NITRIC acid is OBTAINED.