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In passing `3F` of electricity through three electrolytic cells connect in series containing `Ag^(o+),Ca^(2+),` and `Al^(3+)` ions, respectively. The molar ratio in which the three metal ions are liberated at the electrodes isA. `1:2:3`B. `3:2:1`C. `6:3:2`D. `3:4:2` |
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Answer» Correct Answer - C `Ag^(+)+e^(-)rarrAg` `Ca^(2+)+2e^(-)rarrCa` `Al^(3+)+3e^(-)rarrAl` 3 farad aya li berate 1 mol of Al, 3 moles of Ag and 3/2 moles of Cu. Thus, molar ratio of Ag:Cu: Al is 3:3/2 :1 or 6:3:2. |
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