In PCl_(5), phosphorus is in sp^(3) d hybridised state but all its five bonds are not equivalent. Justify your answer with reason.

In PCl_(5), phosphorus is in sp^(3) d hybridised state but all its fiv

1.	In PCl_(5), phosphorus is in sp^(3) d hybridised state but all its five bonds are not equivalent. Justify your answer with reason.
Answer» Solution :`PCl_(5)` has trigonal bipyramid geometry. (Fig. 11.35, page 11/134). It has three equatiorial and two axial bonds. SINCE each axial P-Cl bond is repelle by three bond pairs and each erquatorial P-Cl bond is repelled by only two bond pairs, THEREFORE, axial BANDS are longer are longer (240 pm) than equatroial bonds (202 pm). Thus, all the five P-Cl bonds in `PCl_(5)` are not equivalent.