In `PCl_(5)`, phosphorus is in `sp^(3)` d hybridised state but all its five bonds are not equivalent. Justify your answer with reason.

In `PCl_(5)`, phosphorus is in `sp^(3)` d hybridised state but all its

1.	In `PCl_(5)`, phosphorus is in `sp^(3)` d hybridised state but all its five bonds are not equivalent. Justify your answer with reason.
Answer» `PCl_(5)` has trigonal bipyramid geometry. (Fig. 11.35, page 11/134). It has three equatiorial and two axial bonds. Since each axial P-Cl bond is repelle by three bond pairs and each erquatorial P-Cl bond is repelled by only two bond pairs, therefore, axial bands are longer are longer (240 pm) than equatroial bonds (202 pm). Thus, all the five P-Cl bonds in `PCl_(5)` are not equivalent.

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In `PCl_(5)`, phosphorus is in `sp^(3)` d hybridised state but all its five bonds are not equivalent. Justify your answer with reason.

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