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In photons of energy 12.75 eV are passing through hydrogen gas in ground state then no. of lines in emission spectrum will beA. 6B. 4C. 3D. 2

Answer» Correct Answer - A
`12.75=|E_(0)-(E_(0))/(n^(2))|=|-13.6-((-13.6)/(n_(1)^(2)))|`
`impliesn=4`
no. of lines `=(n(n-1))/(2)=6`


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