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In potentiometer experiment, if l1 is the balancing length for e.m.f. of cell of internal resistance r and l2 is the balancing length for its terminal potential difference when shunted with resistance R then:(A) l1 = l2 \((\frac{R+r}{R})\)(B) l1 = l2 \((\frac{R}{R+r})\)(C) l1 = l2 \((\frac{R}{R-r})\)(D) l1 = l2 \((\frac{R-r}{R})\) |
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Answer» (A) l1 = l2 \((\frac{R+r}{R})\) |
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