In ∆ , PQ = PR and ∠Q = 700, find ∠P.

1.	In ∆ , PQ = PR and ∠Q = 700, find ∠P.
Answer» <P>Answer: in triangle PQR, ↬P=PR. Therefore PQR is an isosceles triangle. ↬therefore, ANGLE Q= angle R(because angles opposite ↬to equal sides of an isosceles triangle are equal) ↬angle P +angle Q + angle R= 180°(angle sum PROPERTY) ↬2angle Q + angle P = 180°(angle Q= angle R) ↬2angle Q=180°-70° ↬angle Q= 110°/2 ↬angle Q=55°=angle $\\$

Answer»

<P>Answer:

in triangle PQR,

↬P=PR. Therefore PQR is an isosceles triangle.

↬therefore, ANGLE Q= angle R(because angles opposite ↬to equal sides of an isosceles triangle are equal)

↬angle P +angle Q + angle R= 180°(angle sum PROPERTY)

↬2*angle Q + angle P = 180°(angle Q= angle R)

↬2*angle Q=180°-70°

↬angle Q= 110°/2

↬angle Q=55°=angle

$\\$

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