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In ∆ , PQ = PR and ∠Q = 700, find ∠P.

Answer» <html><body><p>&lt;<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>&gt;<strong>Answer:</strong></p><p></p><p></p><p>in triangle PQR,</p><p>↬P=PR. Therefore PQR is an isosceles triangle.</p><p>↬therefore, <a href="https://interviewquestions.tuteehub.com/tag/angle-875388" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLE">ANGLE</a> <a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a>= angle <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>(because angles opposite ↬to equal sides of an isosceles triangle are equal)</p><p>↬angle P +angle Q + angle R= 180°(angle sum <a href="https://interviewquestions.tuteehub.com/tag/property-1170155" style="font-weight:bold;" target="_blank" title="Click to know more about PROPERTY">PROPERTY</a>)</p><p>↬2*angle Q + angle P = 180°(angle Q= angle R)</p><p>↬2*angle Q=180°-70°</p><p>↬angle Q= 110°/2</p><p>↬angle Q=55°=angle </p><p></p><p><img align="absmiddle" alt="\\" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%20%5C%5C%20" title="\\"/></p><p></p><p></p><p></p><p></p><p></p></body></html>


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