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In previous question discuss the case when body move downward, upwards and remainsat same position when we increases temperature. |
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Answer» Solution :LET `f =` fraction of volume of body submerged in liquid. `f =("volume of body submerged in liquid")/("TOTAL volume of body")` `f_(1) = (v_(1))/(v_(0)) at theta_(1)^(@)C` `f_(2) = (v_(2))/(v_(0)(1+3 alpha_(s)Delta theta)) at theta_(2)^(@)C` for equilibrium `mg B = v_(1) d_(1)g = v_(2)d_(2)g`. so `v_(2) = (v_(1)d_(1))/(d_(2)) :. d_(2) = (d_(1))/(1+gamma_(L)Delta theta) = v_(1) (1+ gamma_(L) Delta theta) :. f_(2) = (f_(1)(1+gamma_(L)Delta theta))/(v_(0)(1+3alpha_(s)Deltatheta))` where `Delta theta = theta_(2)- theta_(1)` Case I: Body MOVE downward if `f_(2) gt f_(1)` means `gamma_(L) gt 3 alpha_(s)` Case II: Body move upwards if `f_(2) lt f_(1)` means `gamma_(L) gt 3 alpha_(s)` Case III: Body remains at some position if `f_(2) = f_(1)` means `gamma_(L) = 3 alpha_(s)` |
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