In quadrilateral ABCD, angle BAC = angle ACD and angle CAD = angle ACB, then prove that ABCD is parallelogram.

In quadrilateral ABCD, angle BAC = angle ACD and angle CAD = angle ACB

1.	In quadrilateral ABCD, angle BAC = angle ACD and angle CAD = angle ACB, then prove that ABCD is parallelogram.
Answer» rilateral ABCD, angle BAC = angle ACD and angle CAD = angle ACB, then prove that ABCD is parallelogram.(i) ∠COD=65 o [ GIVEN ] ⇒ ∠COD=∠AOB [ Vertically opposite angles ] ∴ ∠AOB=65 oIn △AOB, ⇒ ∠BAC+∠AOB+∠ABO=180 o [ Sum of angles of a triangle is 180 o . ] ⇒ 35 o +65 o +∠ABO=180 o . ⇒ 100 o +∠ABO=180 o ⇒ ∠ABO=80 o ∴ ∠ABD=80 IS THE ANSWER

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In quadrilateral ABCD, angle BAC = angle ACD and angle CAD = angle ACB, then prove that ABCD is parallelogram. ​

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In quadrilateral ABCD, angle BAC = angle ACD and angle CAD = angle ACB, then prove that ABCD is parallelogram.