In qualitative analysis, the metals of Group I can be separated from other ions by precipitating them as chloride salts. A solution initially contains Ag^(+) and Pb^(2+) at a concentration of 0.10 M. Aqueous HCl is added to this solution until the Cl^(-) concentrations of Ag^(+) and Pb^(2+) at equilibrium ? (K_(sp) "for" AgCl=1.8xx10^(-10), K_(sp) "for" PbCl_(2)=1.7xx10^(-5))

In qualitative analysis, the metals of Group I can be separated from o

1.	In qualitative analysis, the metals of Group I can be separated from other ions by precipitating them as chloride salts. A solution initially contains Ag^(+) and Pb^(2+) at a concentration of 0.10 M. Aqueous HCl is added to this solution until the Cl^(-) concentrations of Ag^(+) and Pb^(2+) at equilibrium ? (K_(sp) "for" AgCl=1.8xx10^(-10), K_(sp) "for" PbCl_(2)=1.7xx10^(-5))
Answer» `[AG^(+)]=1.8xx10^(-7) M , [Pb^(2+)]=1.7xx10^(-6)M` `[Ag^(+)]=1.8xx10^(-11) M , [Pb^(2+)]=8.5xx10^(-5)M` `[Ag^(+)]=1.8xx10^(-9) M , [Pb^(2+)]=1.7xx10^(-3)M` `[Ag^(+)]=1.8xx10^(-11) M , [Pb^(2+)]=8.5xx10^(-4)M` Solution :`K_(SP) ` for `AgCl = [Ag^(+)][Cl^(-)]` `:. 1.8xx10^(-10)=[Ag^(+)][0.1]` or`[Ag^(+)]=1.8xx10^(-9)M` `K_(sp)` for `PbCl_(2) = [Pb^(2+)][Cl^(-)]^(2)` `:.1.7xx10^(-5)=[Pb^(2+)][0.1]^(2)` or `[Pb^(2+)]=1.7xx10^(-3)M`.