In question number 7,the temperatureof other interfaces(in .^(@)C) is

1.	In question number 7,the temperatureof other interfaces(in .^(@)C) is
Answer» `26.5, 0.5` `27.5, 1` `28.5, 2` `29.5, 3` Solution :`T_(1) = 27-(Ht_(1))/(K_(1)A_(1)) = 27-0.52 = 26.48^(@)C= 26.5^(@)C` and `T_(2) = 0+ (Ht_(1))/(K_(1)A_(1)) = 0.52^(@)C`

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