In questionnumber91,what willbe the change in the diameter of the rope

1.	In questionnumber91,what willbe the change in the diameter of the rope ?
Answer» `8.8 xx 10^(-9)m` `7.4 xx 10^(-9)m` `6.4 xx 10^(-8)m` `5.6 xx 10^(-9)m` Solution :POISSON's ratio, `SIGMA =(DeltaD//D)/(Deltal//l) = (DeltaD)/(D) .(l)/(Deltal)` `THEREFORE DeltaD = (sigma D Deltal)/(l) = (0.2 xx 6xx 10^(-3) xx 3.32 xx10^(-5))/(4.5)= 8.8 xx 10^(-9)m`

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