Saved Bookmarks
| 1. |
In resonance tube experiment , the velocity of sound is given by `v = 2 f_(0) ( l_(2) - l_(1))` . We found `l_(1)=25.0 cm` and `l_(2)=75.0 cm`. If there is no error in frequency, what will be the maximum permissible errror in the speed of sound ? (Take `f_(0) = 325 Hz`)A. `0.2m//s`B. `0.65m//s`C. `1.3m//s`D. `2.6m//s` |
|
Answer» Correct Answer - C `V=2f_(0)(l_(2)-l_(1))`, `(dv)=2f_(0)(dl_(2)-dl_(1))` `(dv)_(max)=max of [2f_(0)(+-Deltal_(2)overset(-)(+)Deltal_(2))]` `=2f_(0)(Deltal_(2)+Deltal_(1))` `l_(1)=25.0cm` `impliesDeltal_(1)=0.1cm` (place value of last number) `l_(1)=75.0cm` `implies Deltal_(2)=0.1cm`(place value of last number) So max permissible error `i` speed of sound `(dv)_(max)=2(325Hz)(0.1cm+0.1cm)` `=1.3m//s` `V=2f_(0)(l_(2)-l_(1))` `=2(325Hz)(75.0cm-25.0cm)=325m//s` so `V=(325+-1.3)m//s` |
|