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In resonance tube first resonance is obtain at 20 cm, then third resonance length will be: (frequency of source = 400 Hz, speed of sound in air = 336 m/s)(a) 60 cm(b) 104 cm.(c) 64 cm(d) 100 cm |
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Answer» Correct option is (b) 104 cm. Wavelength of wave ⇒ λ = v/f = 336/400 = 84 cm At first resonance λ/4 = l + e ⇒ 84/4 = 20 + e ⇒ e = 1 So third resonance length 5 λ/4 = l2 + e 5(21) = l2 + 1 l2 = 104 cm |
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