1.

In resonance tube first resonance is obtain at 20 cm, then third resonance length will be: (frequency of source = 400 Hz, speed of sound in air = 336 m/s)(a) 60 cm(b) 104 cm.(c) 64 cm(d) 100 cm

Answer»

Correct option is (b) 104 cm.

Wavelength of wave ⇒ λ = v/f = 336/400 = 84 cm

At first resonance

λ/4 = l + e ⇒ 84/4 = 20 + e

⇒ e = 1

So third resonance length

5 λ/4 = l+ e

5(21) = l+ 1

l= 104 cm



Discussion

No Comment Found

Related InterviewSolutions