In right angle triangle ABC, 8em, 15 cm and 17 cm are the lengths of A

1.	In right angle triangle ABC, 8em, 15 cm and 17 cm are the lengths of AB, BC and Crespectively. Then, find out sin A, cos A and tan A.DD = 25 cm and LO = 9
Answer» According to the question, AB = 8 cm, BC = 15 cm, AC = 17 cm According to the diagram, AB = AdjacentSide, BC = Opposite Side, AC = Hypotenuse. Now we need to find Sin A, Cos A, and Tan A. Let us calculate Sin A first, Sin A = Opposite / Hypotenuse => Sin A = BC / AC => Sin A = 15 / 17 Cos A = Adjacent / Hypotenuse => Cos A = AB / AC => Cos A = 8 / 17 Tan A = Opposite / Adjacent => Tan A = BC / AB => Tan A = 15 / 8

In right angle triangle ABC, 8em, 15 cm and 17 cm are the lengths of AB, BC and Crespectively. Then, find out sin A, cos A and tan A.DD = 25 cm and LO = 9

Answer»

According to the question,

AB = 8 cm, BC = 15 cm, AC = 17 cm

According to the diagram,

AB = AdjacentSide, BC = Opposite Side, AC = Hypotenuse.

Now we need to find Sin A, Cos A, and Tan A.

Let us calculate Sin A first,

Sin A = Opposite / Hypotenuse

=> Sin A = BC / AC

=> Sin A = 15 / 17

Cos A = Adjacent / Hypotenuse

=> Cos A = AB / AC

=> Cos A = 8 / 17

Tan A = Opposite / Adjacent

=> Tan A = BC / AB

=> Tan A = 15 / 8