In right angled ALMN, if ZN = 0, ZM = 90°,cos 0 = find sin 0 and tanS

1.	In right angled ALMN, if ZN = 0, ZM = 90°,cos 0 = find sin 0 and tanSimilarly, find (sin ) and (cos 6).MFig. 8.28
Answer» sinQ = 7/25tanQ =7/24sin²Q=49/625cos²Q=576/625 answers of both questions are - 49/625 and 576/625 sinQ= 7/25tanQ= 7/24sin2(sin square)Q= 49/625cos2(cos square)Q= 576/625 579/625 is the correct answer in right angled Lmn sinQ=7/25tanQ=7/24sin2Q=49/625cos2Q=576/625 sin q = 7/25tan q =7/24sin²q=49/625cos²q=576/625 sinQ=7/25 and cosQ=24/25and tan Q=7/24 sin square equal to answer hoga 47 /625 the question answer is sinQ=7/25 tanQ7/24sin2Q=49/625cos2Q=576/625 given that cosQ= 24/25and we know that sinQ=7/25tanQ= 7/24 sinQ=7/25tanQ=7/24sin=49/625cos=576/625 NaN 45 2.7

In right angled ALMN, if ZN = 0, ZM = 90°,cos 0 = find sin 0 and tanSimilarly, find (sin ) and (cos 6).MFig. 8.28

Answer»

sinQ = 7/25tanQ =7/24sin²Q=49/625cos²Q=576/625

answers of both questions are - 49/625 and 576/625

sinQ= 7/25tanQ= 7/24sin2(sin square)Q= 49/625cos2(cos square)Q= 576/625

579/625 is the correct answer

in right angled Lmn

sinQ=7/25tanQ=7/24sin2Q=49/625cos2Q=576/625

sin q = 7/25tan q =7/24sin²q=49/625cos²q=576/625

sinQ=7/25 and cosQ=24/25and tan Q=7/24

sin square equal to answer hoga 47 /625

the question answer is sinQ=7/25 tanQ7/24sin2Q=49/625cos2Q=576/625

given that cosQ= 24/25and we know that sinQ=7/25tanQ= 7/24

sinQ=7/25tanQ=7/24sin=49/625cos=576/625

NaN 45 2.7