1.

In S.H.M., the velocity of the particle at the mean position is 1 m/s and acceleration at the extremity is `2 m//s^(2)`, the period of motion isA. 2 sB. 0.5 sC. 1 sD. 3.142 s

Answer» Correct Answer - D
`(a_(m))/(v_(m))=omega" "therefore omega=(2)/(1)=2`
`T=(2pi)/(omega)=(2pi)/(2)=pim//s`
`T=3.142s`


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