Saved Bookmarks
| 1. |
In s series of successive measurements in an experiment, the readings of the period of oscillation of a simple pendulum were found to be 2.63s,2.56s,2.42s,2.71s" and "2.80s. Calculate The mean absolute error in each measurement. |
|
Answer» SOLUTION :`t_1= 2.63s, t_2=2.56s, t_3=2.42s, t_4= 2.71s, t_5= 2.80s` ABSOLUTE ERROR `triangleT =T_m -t` `triangleT_1= 2.62-2.63=0.01s` `TRIANGLE T_2= 2.62-2.56= +0.06s` `triangleT_3= 2.62-2.42= +0.20s` `triangleT_4=2.62-2.71= -0.09s` `triangleT_5= 2.62-2.80= -0.18s`. |
|