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In s series of successive measurements in an experiment, the readings of the period of oscillation of a simple pendulum were found to be 2.63s,2.56s,2.42s,2.71s" and "2.80s. Calculate The percentage error. Express the results in proper form. |
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Answer» SOLUTION :`t_1= 2.63s, t_2=2.56s, t_3=2.42s, t_4= 2.71s, t_5= 2.80s` PERCENTAGE ERROR in `T= 0.04xx 100%= 4%`. |
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