1.

In secont excited state of cl find the maximum sum of n+l+m for unpaired electrons

Answer»

4Explanation:The MAXIMUM VALUE of (N+l+m) for all the unpaired electrons of CHLORINE in its second excited state .ELECTRONIC configuration of chlorine atom1s22s22p63s23p5First exited state chlorine atom1s22s22p63s13p6Second exited state chlorine atom1s22s22p63s03p64s1For only one unpaired electron present present in 4s orbitalValue of n =4Value of l =0Value of m =0Therefore , the maximum value of (n+l+m) for all the unpaired electrons if chlorine in its second excited state .=4+0+0=4



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