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In SHM, amplitude of kintetic energy is ((l)/(4))^(th) of the total energy at a displacementequal to: |
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Answer» `(A)/(sqrt(2))` Kinetic energy, `k=(1)/(2) m omega A^(2)(A^(2)-X^(2))` Total energy `E=(1)/(2)m omega^(2)A^(2)` As, `k=(E)/(4)` `:. (1)/(2)m omega^(2)(A^(2)-x^(2))=(1)/(4)((1)/(2)m omega^(2)A^(2))` (or) `4A^(2)-4X^(2)=A^(2)` (or) `4x^(2)=3A^(2)x` (or) `x=(sqrt(3))/(2)A` |
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