1.

In `SiF_(6)^(-2)` because of small size of FA. `SiF_(6)^(-2)` because of small size of FB. `SiF_(6)^(-2)` because of large size of FC. `SiCl_(6)^(-2)` because of small size of ClD. `SiCl_(6)^(-2)` because of large size of Cl

Answer» Correct Answer - A::B::C::D


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