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In solid oxide are arranged in ccp .One - sixth of tetrabedral voids are occupied by cation A which one third of octahedral voids are occupied by cation `B` .What is the formula of compound ?A. `A_(2)BO_(3)`B. `ABO_(3)`C. `AB_(2)O_(3)`D. `A_(2)B_(2)O_(3)`

Answer» Correct Answer - B
Suppose `O^(2-)` ions = n . Then octahedral voids = n,
tetrahedral voids = 2 n
Cations A present `=(1)/(6)xx2n=(n)/(3)` .
Cations B present `=(1)/(3)xxn=(n)/(3)`.
`:.` Ratio `A:B:O^(2-)=(n)/(3):(n)/(3):n=1:1:3` .
Hence, , formula is `ABC_(3)`


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