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In solid `PCl_(5)` exist as `[PCl_(4)]^(+) [PCl_(6)]^(-)`. The hybridisation is P is /areA. `sp^(3)`B. `sp^(3)d`C. `sp^(3)d^(2)`D. `sp^(3) d^(3)` |
Answer» Correct Answer - A::C | |