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In space of horizontal `EF (E = (mg)//q)` exist as shown in figure and a mass m is released at the end of a light rod. If mass m is releases from the position shown in figure find the angular velocity of the rod when it passes through the bottom most position .A. `sqrt((g)/(l))`B. `sqrt((2g)/(l))`C. `sqrt((3g)/(l))`D. `sqrt((5g)/(l))` |
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Answer» Correct Answer - B `W_(E)+W_(g)=DeltaK.E` Use work energy theorem `(Eq)l sintheta+mgl(1-costheta)=(1)/(2)IomegaQ^(2)` |
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