In sulphur estimation, 0.157 g of an organic compound gave 0.4813 g of barium sulphate. What is the percentage of sulphur in the compound ? (Ba = 136, S= 32, O= 16)

In sulphur estimation, 0.157 g of an organic compound gave 0.4813 g of

1.	In sulphur estimation, 0.157 g of an organic compound gave 0.4813 g of barium sulphate. What is the percentage of sulphur in the compound ? (Ba = 136, S= 32, O= 16)
Answer» SOLUTION :molar mass of `BaSO_(4) = Ba + S + 4(O)` `= 137 + 32 + 64` = 233g `underset(32g)(S ) overset(NHO_(3))RARR H_(2)SO_(4) overset(BaCl_(2))rarr underset(233g)(BaSO_(4))` `:. 233g BaSO_(4)` contain 32g sulphur 0.4813g `BaSO_(4)` contain mass of sulphur `= (32 xx 0.4813)/(233)gm` %S `= (32)/(233) xx (0.4813)/(0.157) xx 100` = 42.10%