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In sulphur estimation, 0.157 g of an organic compound gave 0.4813g of barium sulphate. What is the percentage of sulphur in the compound ? |
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Answer» Solution :233g `BaSO_(4)` contain 32G sulphur `0.4813g BaSO_(4)` contain `(32 xx 0.4813)/(233)G` sulphur `:.` % of sulphur `= (32 xx 0.4813 xx 100)/(233 xx 0.157) = 42.10` |
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