1.

In sulphur estimation, 0.157 g of an organic compound gives 0.4813 g of barium sulphate. The percentage of sulphur in the compound, is

Answer»

`42.10`
`52.10`
`21.05`
`40.01`

Solution :MOLECULAR mass of `BaSO_(4)=138 +32+64 = 233` G
23 g of `BaSO_(4)` CONTAINS 32 g of sulphur
`:. 0.4813 g` of `BaSO_(4)` will contain
`=(32 xx 0.4813)/(233)` g of sulphur
`%` of `S=(32 xx 0.4813xx100)/(233xx0.157)=42.10`.


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