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In sulphur estimation, 0.157 g of an organic compound gives 0.4813 g of barium sulphate. The percentage of sulphur in the compound, is |
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Answer» `42.10` 23 g of `BaSO_(4)` CONTAINS 32 g of sulphur `:. 0.4813 g` of `BaSO_(4)` will contain `=(32 xx 0.4813)/(233)` g of sulphur `%` of `S=(32 xx 0.4813xx100)/(233xx0.157)=42.10`. |
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