In sulphur estimation of 0.157 h of an organic compound gave 0.4813 g

1.	In sulphur estimation of 0.157 h of an organic compound gave 0.4813 g of barium sulphate. What is the percentage of sulphur in the compound?[At. Mass of (a) Barium = 137 u (b) Sulphur = 32 u (c) Oxygen = 16 u]
Answer» Mass of organic compound = 0.157 g Mass of BaSO₄ = 0.4813 g Percentage of sulphur = \(\frac{32}{233}\) x \(\frac{Mass\,of\,BaSO_4}{Mass\,of\,organic\,compound}\) x 100 = \(\frac{32}{233}\) x \(\frac{0.4813}{0.157}\) x 100 = 42.10 %

In sulphur estimation of 0.157 h of an organic compound gave 0.4813 g of barium sulphate. What is the percentage of sulphur in the compound?[At. Mass of (a) Barium = 137 u (b) Sulphur = 32 u (c) Oxygen = 16 u]

Answer»

Mass of organic compound = 0.157 g

Mass of BaSO₄ = 0.4813 g

Percentage of sulphur = \(\frac{32}{233}\) x \(\frac{Mass\,of\,BaSO_4}{Mass\,of\,organic\,compound}\) x 100

= \(\frac{32}{233}\) x \(\frac{0.4813}{0.157}\) x 100

= 42.10 %