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    				| 1. | In terms of basic units of mass (M), length (L), time (T), and charge (Q), the dimensions of magnetic permeability of vacuum `(mu_0)` would beA. `(MLQ^(-2))`B. `(LT^(-1) Q^(-1))`C. `(ML^2 T^(-1)Q^(-2))`D. `(LTQ^(-1))` | 
| Answer» Correct Answer - (a) Force acting per unit length of eacth of two parallel wires carrying currents in the same direction placed certain distance apart in vacuum is `(F)/(I) = (mu_0)/(4pi). (2I_1II_2)/(r )` `(MLT^(-2))/(L) = mu_0 ((Q//T)^2)/(L) or mu_0 = [MLQ^(-2)]` | |