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In terms of Charles. law explain why -273^(@)C is the lowest possible temperature. |
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Answer» Solution :Eq. of Charle.s : `V_(t)=V_(0)((273.15+t)/(273.15))`….(Eq.-i) Put `t=-273/15^(@)C` in above equation. `THEREFORE V_(t)=V_(0)((273.15-273.5)/(273.15))` `therefore V_(t)=V_(0)((0)/(273.15))` `therefore V_(t)=0=V_(-273.15)` Therefore the VOLUME BECOME zero at the temperature `- 273.15^(@)C`. Actually all the GASES liquifies before reaching such low absolute `(-273.15^(@)C)` temperature and this is the least probable temperature. At this `- 273.15^(@)C` temperature the volume of the gases is zero and it is called absolute zero. |
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