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1. |
In that figure, if `Delta ABE ~= Delta ACD`, show that `Delta ADE ~= Delta ABC`. |
Answer» `Delta ABE~= Delta ACD` (give) `:. AE= AD" "...(i)` [cpct] and `AB =AC" "...(ii)` [ cpct] In `Delta ADE and Delta ABC`, we have `angle DEA= angle BAC` (common) and `(AD)/(AB)=(AE)/(AC)" "` [ using (i) and (ii)] `:. Delta ADE ~ Delta ABC`[ by SAS-similarity] |
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