1.

In the ∆ABC, exterior angle at ∠C = 105° and ∠A = 65°. Find the other interior opposite angle.

Answer»

Given that, exterior angle at ∠C = 105°. 

One of the interior opposite angle ∠A = 65°. 

The other interior opposite angle is ∠B . ∠A + ∠B =105°(∵ Exterior angle property of a triangle) 

65° + ∠B = 105° 

⇒ ∠B = 105° – 65° = 40°



Discussion

No Comment Found

Related InterviewSolutions