In the above example, calculate the amplitude of motion.

1.	In the above example, calculate the amplitude of motion.
Answer» Solution :Initial VELOCITY V = 5 `ms^(-1)` Final veloctiy of system = V After collision Using law of conservation of LINEAR momentum We have `mv = (m + M)V` m = 0.1 kg `M = 0.5` kg ` 0.1 XX 5 = (0.1 + 0.5)V` `(0.1 xx 5)/(0.6) = V` `0.83 ms^(-1)` = V Maximum kinetic energy of system `(1)/(2) (m + M)V^(2)` According to law of conversation of energy . Maximum K.E. = Maximum P.E. `(1)/(2)(m + M)V^(2) = (1)/(2)kv^(2)` `rArr a^(2) = (2)/(2) ((m + M)V^(2))/(k)` `a = Vsqrt((m + M)/(k)) = 0.83 SQRT((0.1 + 0.5))/(500)` = 0.02 m

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