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In the above example the angular velocity of S_(2) as actually observed by an astronaut in S_(1) is - |
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Answer» `3xx10^(-4)` `omega_(r )=(|v_(1)-v_(2)|)/(|r_(2)-r_(1)|)` `|v_(1)-v_(2)|=(2pixx10^(4)-pixx10^(4))km//h` `or |v_(1)-v_(2)|=(pixx10^(4)xx1000)/(60xx60)m//s` `or |v_(1)-v_(2)|=(3.14xx10^(5))/(36)=0.0872xx10^(5)=8.72xx10^(3) m//s` `|r_(2)-r_(1)|=3xx10^(7) m` `:. omega_(r )=(8.72xx10^(3))/(3xx10^(7))=2.9xx10^(-4)~~3xx10^(-4) rad//sec` `:. omega_(r )=3xx10^(-4) rad//sec.` |
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