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In the above problem, what is the angle of projection with horizontal ?A. `tan^-1 (1//4)`B. `tan^-1 (4//3)`C. `tan^-1 (3//4)`D. `tan^-1 (1//2)` |
Answer» Correct Answer - B (b) `tan theta = (v_y)/(v_x) = (8)/(6) = (4)/(3) or theta = tan^-1 (4)/(3)`. |
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