Saved Bookmarks
| 1. |
In the above question, the speed of each ball relative to ground just after they leave the disc is -A. `(Romega_(0))/(sqrt3)`B. `(Romega_(0))/(sqrt2)`C. `(2Romega_(0))/(3)`D. None of these |
|
Answer» Correct Answer - 3 The angular speed of the disc just after the balls leave the disc is `omega=(omega_(0))/(3)` Let the speed of each ball just after they leave the disc be v. From conservation of energy `(1)/(2)[(1)/(2)mR^(2)]omega_(0)^(2)=(1)/(2)[(1)/(2)mR^(2)]omega^(2)+(1)/(2)[("m")/(2)]v^(2)+(1)/(2)[("m")/(2)]v^(2)` solving we get `v=(2Romega_(0))/(3)` NOTE : `v=sqrt((omegaR)^(2)+V_(r)^(2)) , V_(r)` = radial velocity of tha ball |
|