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In the absence of wind the range and maximum height of a projectile were R and H. If wind imparts a horizontal acceleration a = g/4 to the projectile then find the maximum range and maximum height. |
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Answer» Solution :`H^(1) = H (because u SIN THETA " REMAINS same")` `T^(1) = T` `R^(1) = u_(x)T + (1)/(2) a T^(2) = R + (1)/(2) (g)/(4)T^(2)` `= R = (1)/(8) g T^(2) = R + H` `R^(1) = R + H` `H^(1) = H` |
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