1.

In the absence of wind the range and maximum height of a projectile were R and H. If wind imparts a horizontal acceleration a = g/4 to the projectile then find the maximum range and maximum height.

Answer»

Solution :`H^(1) = H (because u SIN THETA " REMAINS same")`
`T^(1) = T`
`R^(1) = u_(x)T + (1)/(2) a T^(2) = R + (1)/(2) (g)/(4)T^(2)`
`= R = (1)/(8) g T^(2) = R + H`
`R^(1) = R + H`
`H^(1) = H`


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