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In the adjacent figure, CD and BE are altitudes of an isosceles triangle ABC with AC = AB prove that AE = AD. |
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Answer» In ∆ADC and ∆AEB AC = AB [data] ∠ADC = ∠AEB[BE & CD altitudes] ∠DAC =∠EAB [Common angle] ∆ ADC = ∆ AEB[AS∆postulate] AD=AE [Corresponding sides] |
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