1.

In the adjacent figure if quadrilateral PQRS circumscribes a circle, then PB + SD =(A) SR (B) PR (C) QS (D) PS

Answer»

Correct option is: (D) PS

Lengths of tangents from a fixed outer point to circle are equal.

\(\therefore\) PB = PA (Tangents drawn from outer point P)

and SD = AS (Tangents drawn from outer point  S)

\(\therefore\) PB + SD = PA + AS = PS

Correct option is: (D) PS



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