InterviewSolution
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In the adjacent figure if quadrilateral PQRS circumscribes a circle, then PB + SD =(A) SR (B) PR (C) QS (D) PS |
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Answer» Correct option is: (D) PS Lengths of tangents from a fixed outer point to circle are equal. \(\therefore\) PB = PA (Tangents drawn from outer point P) and SD = AS (Tangents drawn from outer point S) \(\therefore\) PB + SD = PA + AS = PS Correct option is: (D) PS |
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