In the adjoining figure AB= AC and D is the mid-point of BC. Use SSS r – InterviewSolution

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1.	In the adjoining figure AB= AC and D is the mid-point of BC. Use SSS rule of congruency to show that `triangle ABD ~=triangle ACD` AD is bisector of `angle A` AD is perpendicular to BC
Answer» In`/_ABD and /_ACD` AB=AC(GIVEN) BD=DC(D is mid point of BC) AD=AD so,`/_ABDcong/_ACD` so, `angleBAD=angleCAD` and`angleADB=angleADC=180^o/2=90^o` this means AD is perpendicular BC

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