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In the adjoining figure ∆ABCD and ∆PBCQ are parallelogram BC = 12 cm PR = 8cm. Find A (∆PSB). (1) 96 cm2 (2) 72 cm2 (3) 48 cm2 (4) 36 cm2 |
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Answer» (3) 48 cm2 \(\frac{1}{2}\)[PQCB] = [PSB] \(\frac{1}{2}\)x 8 x 12 = [PSB] [PSB] = 48 |
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