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In the adjoining figure, in AABC, seg AD and seg BE are altitudes and AE = BD. Prove that seg AD = seg BE |
Answer» Proof: In ∆ADB and ∆BEA, seg BD ≅ seg AE [Given] ∠ADB ≅ ∠BEA = 90° [Given] seg AB ≅ seg BA [Common side] ∴ ∆ADB ≅ ∆BEA [Hypotenuse-side test] ∴ seg AD ≅ seg BE [c. s. c. t.] |
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