1.

In the adjoining figure, in AABC, seg AD and seg BE are altitudes and AE = BD. Prove that seg AD = seg BE

Answer»

Proof: 

In ∆ADB and ∆BEA, seg BD ≅ seg AE [Given] 

∠ADB ≅ ∠BEA = 90° [Given] 

seg AB ≅ seg BA [Common side] 

∴ ∆ADB ≅ ∆BEA [Hypotenuse-side test] 

∴ seg AD ≅ seg BE [c. s. c. t.]



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