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In the adjoining figure, point O is the centre of the cirlcle, seg OM ⊥ chord AB. If OM = 8 cm, AB = 12 cm, then find OB. |
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Answer» MB = 1/ 2 × AB = 1 / 2 × 12 = 6 cm (perpendicular drawn from the centre of the circle to the chord bisects the chord) OB2 = OM2 + MB2 .....................(Pythagoras theorem) = 82 + 62 = 64 + 36 = 100 ∴ OB = 10 cm |
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