1.

In the adjoining figure, point O is the centre of the cirlcle, seg OM ⊥ chord AB. If OM = 8 cm, AB = 12 cm, then find OB.

Answer»

MB = 1/ 2 × AB = 1 / 2 × 12 = 6 cm (perpendicular drawn from the centre of the circle to the chord bisects the chord)

OB2 = OM2 + MB2 .....................(Pythagoras theorem) 

= 82 + 6

= 64 + 36 

= 100 ∴ OB 

= 10 cm



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